36-25x+4x^2=0

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Solution for 36-25x+4x^2=0 equation:



36-25x+4x^2=0
a = 4; b = -25; c = +36;
Δ = b2-4ac
Δ = -252-4·4·36
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-7}{2*4}=\frac{18}{8} =2+1/4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+7}{2*4}=\frac{32}{8} =4 $

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